The heat evolved in the combustion of methane is given by the following equations ${\rm{C}}{{\rm{H}}_4}\left( {\rm{g}} \right) + 2{{\rm{O}}_2}\left( {\rm{g}} \right) \to {\rm{C}}{{\rm{O}}_2}\left( {\rm{g}} \right) + {{\rm{H}}_2}{\rm{O}}\left( l \right);\Delta H = - 890.3{\rm{kJ}}$ How many grams of methane would be required to produce 44.15 kJ of heat of combustion?Failed to load question data. Please try again later.
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