The formation of the oxide ion ${{\rm{O}}^{2 - }}\left( {\rm{g}} \right)$ requires first an exothermic and then an endothermic step as shown below ${\rm{O}}\left( {\rm{g}} \right) + {e^ - } = {{\rm{O}}^ - }\left( {\rm{g}} \right);{\rm{\;\;}}\Delta {H^o} = - 142{\rm{\;kJ\;mo}}{{\rm{l}}^{ - 1}}$ , ${{\rm{O}}^ - }\left( {\rm{g}} \right) + {e^ - } = {{\rm{O}}^{2 - }}\left( {\rm{g}} \right),{\rm{\;}}\Delta {H^o} = 844{\rm{\;kJ\;mo}}{{\rm{l}}^{ - 1}}$ This is becauseFailed to load question data. Please try again later.
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