The combustion of benzene $(l)$ gives $C{O_2}\left( g \right)$ and ${H_2}O\left( l \right)$. Given that heat of combustion of benzene at constant volume is $-3263.9\,kJ\,mo{l^{ - 1}}$ at $ 25^\circ C$, heat of combustion (in $kJ\,\,mo{l^{ - 1}}{\rm{)}}$ of benzene at constant pressure will be <Br> $\left( {R = 8.314\,J{K^{ - 1}}\,mo{l^{ - 1}}} \right)$Failed to load question data. Please try again later.
NEET Information
- NEET 2024
- NEET Syllabus
- NEET Application Process
- NEET Seat Intake