The cathodic reaction of a dry cell is represented by <br>
$2{\rm{Mn}}{{\rm{O}}_2}\left( s \right) + {\rm{Z}}{{\rm{n}}^2} + 2{e^ - } \to {\rm{ZnM}}{{\rm{n}}_2}{{\rm{O}}_4}\left( s \right)$ <br>
If , there are 8 g of ${\rm{Mn}}{{\rm{O}}_2}$ in the cathodic compartment then the time for which the dry cell will continue to give a current of 2 mA is
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