Which economically important product is obtained from Cycas circinalis?

Sago is obtained from the pith of Cycas circinalis and Cycas revoluta. It is rich in starch and used as constituent of poor man’s food.

Which of the given household product is obtained by using only bacteria?

Dosa is prepared using Leuconostoc and Streptococcus species of bacteria.

The solubility of ${A_2}{B_5}$ is mol. $d{m^{ - 3}}$, its solubility product is

${A_2}{x_5}2{A^{ + 5}} + 5{x^{ - 2}}\,,\,{K_{SP}} = {\left[ {{A^{ + 5}}} \right]^2}{\left[ {{ \times ^{ - 2}}} \right]^5} = {\left( {2x} \right)^2} \times {\left( {5x} \right)^5}$ , $ = 12500\,\,{x^7} = 1.25 \times {10^4}{x^7}$

$64\,\, \times {10^4}\,\,{x^7}$

The correct Option is "$1.25\,\, \times {10^4}\,\,{x^7}$"

Which value of heat of formation indicates that the product is the least stable?

The product possesses maximum energy and thus, least stable.

The correct Option is "$ + 64.8{\rm{kcal}}$"

The solubility of ${A_2}{X_3}$ is $y{\kern 1pt} \,{\rm{mol}}\;{\rm{d}}{{\rm{m}}^{ - 3}}.$ Its solubility product is:

${K_{sp}} = {\left[ {{A^{3 + }}} \right]^2}{\left[ {{X^{2 - }}} \right]^3} = {\left( {2y} \right)^2}{\left( {3y} \right)^3} = 108{y^5}$

$6{\kern 1pt} {\kern 1pt} {y^4}$

$64{\kern 1pt} {\kern 1pt} {y^4}$

$36{\kern 1pt} {\kern 1pt} {y^5}$

The correct Option is "$108{\kern 1pt} {\kern 1pt} {y^5}$"

For ${\rm{PC}}{{\rm{l}}_5}\leftrightharpoons{\rm{PC}}{{\rm{l}}_3} + {\rm{C}}{{\rm{l}}_2}$, initial concentration of each reactant and product is 1 M. If ${K_{{\rm{eq}}}} = 0.41$ then

${K_c} = \frac{{\left[ {{\rm{product}}} \right]}}{{\left[ {{\rm{reactant}}} \right]}}$ $0.41 = \frac{{\left[ {{\rm{product}}} \right]}}{{\left[ {{\rm{reactant}}} \right]}}$ $ \Rightarrow \,\,\left[ {{\rm{product}}} \right] = 0.41 \times \left[ {{\rm{reactant}}} \right]$ $ \Rightarrow \,\,\left[ {{\rm{product}}} \right] Therefore, reaction proceeds in backward direction, $i.e.,$ more ${\rm{PC}}{{\rm{l}}_5}$ will be formed.

More ${\rm{PC}}{{\rm{l}}_3}$ will form

More ${\rm{C}}{{\rm{l}}_2}$ will form

The correct Option is "More ${\rm{PC}}{{\rm{l}}_5}$ will form"

In which of the following reactions, the concentration of product is higher than the concentration of reactant at equilibrium? $\left( {K = \;\;{\rm{equilibrium}}\;{\rm{ constant}}} \right)$

For a reaction, ${K_c} = \frac{{\left[ {{\rm{product}}} \right]}}{{\left[ {{\rm{reactant}}} \right]}}$ Hence, if ${K_c} > 1$, then [Product]>[Reactant]

$A\,\,\leftrightharpoons\,\,B;K = 0.001$

The correct Option is "$M\,\,\leftrightharpoons\,\,N;K = 10$"

$X\,\leftrightharpoons\,\,Y;K = 0.005$

$R\,\leftrightharpoons\,\,P;K = 0.01$

The hydroxide with highest solubility product is:

${\rm{Co}}{\left( {{\rm{OH}}} \right)_2}$ is not precipitated in ${\rm{III }}\;{\rm{gp}}{\rm{.}}$ or it more soluble and thus, has high ${K_{sp}}$.

${\rm{Al}}{\left( {{\rm{OH}}} \right)_3}$

The correct Option is "${\rm{Co}}{\left( {{\rm{OH}}} \right)_2}$"

${\rm{Cr}}{\left( {{\rm{OH}}} \right)_3}$

${\rm{Fe}}{\left( {{\rm{OH}}} \right)_3}$

Anthraquinone is prepared by the oxidation of anthracene by chromic acid. The crude reaction product is usually purified by

Anthracene being sublimable can be separated from anthraquinone by sublimation.

The correct Option is "Sublimation"

A saturated solution of ${\rm{A}}{{\rm{g}}_2}{\rm{S}}{{\rm{O}}_4}\;{\rm{is}}\;2.5 \times {10^{ - 2}}\;{\rm{M}}$ The value of its solubility product is

${\rm{A}}{{\rm{g}}_2}{\rm{S}}{{\rm{O}}_4} \to 2{\rm{A}}{{\rm{g}}^ + } + {\rm{SO}}_4^{2 - }$ ${\rm{A}}{{\rm{g}}_2}{\rm{S}}{{\rm{O}}_4}$ is a 2:1 type electrolyte i.e., it gives two ${\rm{A}}{{\rm{g}}^ + }$ ions and one ${\rm{SO}}_4^{2 - }$ ion on ionisation. Given, $s = 2.5 \times {10^{ - 2}}\;{\rm{M}}$ Hence, its ${K_{{\rm{sp}}}} = 4{s^3}$ (where, s= molar solubility) ${K_{{\rm{sp}}}} = 4{\left( {2.5 \times {{10}^{ - 2}}} \right)^3}$ $ = 4 \times 15.63 \times {10^{ - 6}}$ $ = 62.5 \times {10^{ - 6}}$

The correct Option is "$62.5 \times {10^{ - 6}}$"

The solubility of ${\rm{C}}{{\rm{a}}_3}{\left( {{\rm{P}}{{\rm{O}}_4}} \right)_2}$ in water is y moles/litre. Its solubility product is

$\begin{array}{l} {\rm{C}}{{\rm{a}}_3}{\left( {{\rm{P}}{{\rm{O}}_4}} \right)_2}\left( s \right)\;\leftrightharpoons3{\rm{C}}{{\rm{a}}^{2 + }}\left( {aq} \right) + 2{\rm{PO}}_4^{3 - }\left( {aq} \right)\\ \;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;3y\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;2y \end{array}$ ${K_{{\rm{sp}}}} = {\left[ {{\rm{C}}{{\rm{a}}^{2 + }}} \right]^3}.{\left[ {{\rm{PO}}_4^{3 - }} \right]^2}$ $ = {\left( {3y} \right)^3}.{\left( {2y} \right)^2}$ $ = 27{y^3} \times 4{y^2}$ $ = 108\;{y^5}$

The correct Option is "$108\;{y^5}$"

$Ca{C_2}\xrightarrow{{{H_2}O}}A\xrightarrow[{H{g^{2 + }}}]{{dil.{H_2}S{O_4}}}B\xrightarrow[{{H_2}}]{{Ni}}C$ end product is

$A = {C_2}{H_2},B = C{H_3} - CHO,C = {C_2}{H_5}OH$

The correct Option is "${C_2}{H_5}OH$"

When butane-1 is mixed with excess of bromine, the expected reaction product is:

The correct Option is "1,2-dibromobutane"

When butene-1 is mixed with HBr, the major reaction product is:

${\rm{C}}{{\rm{H}}_3}{\rm{C}}{{\rm{H}}_2}{\rm{CH}} = {\rm{C}}{{\rm{H}}_2}\xrightarrow{{HBr}}{\rm{C}}{{\rm{H}}_3}{\rm{C}}{{\rm{H}}_2}{\rm{CHBrC}}{{\rm{H}}_3}$

The correct Option is "2-bromobutane"

The reaction, ${\rm{C}}{{\rm{H}}_3}{\rm{Br}} + {\rm{Na}} \to product$, is called

It is a common method to prepare alkanes. Methane cannot be prepared by Wurtz reaction. $\begin{array}{l} {\rm{C}}{{\rm{H}}_3}{\rm{Br}} + 2{\rm{Na}} + {\rm{BrC}}{{\rm{H}}_3} \to {{\rm{C}}_2}{{\rm{H}}_6} + 2{\rm{NaBr}}\\ \;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;ethane \end{array}$

The correct Option is "Wurtz reaction"

What is obtained when chlorine is passed in boiling toluene and product is hydrolysed?

When chlorine is passed in boiling toluene, substitution in side-chain takes place and benzyl chloride is obtained which on hydrolysis give benzyl alcohol

The correct Option is "Benzyl alcohol"

${\rm{CuS}}{{\rm{O}}_4}$ decolourises on addition of KCN, the product is:

$2{\rm{CuS}}{{\rm{O}}_4} + 10{\rm{KCN\;}} \to 2{{\rm{K}}_3}{\rm{Cu}}{\left( {{\rm{CN}}} \right)_4} + {\left( {{\rm{CN}}} \right)_2} + 2{{\rm{K}}_2}{\rm{S}}{{\rm{O}}_4}$

${\rm{Cu}}\left( {{\rm{CN}}} \right)_4^{2 - }$

The correct Option is "${\left[ {{\rm{Cu}}{{\left( {{\rm{CN}}} \right)}_4}} \right]^{3 - }}$"

${\rm{Cu}}{\left( {{\rm{CN}}} \right)_2}$

${\rm{C}}{{\rm{H}}_3} - {\rm{C}}{{\rm{H}}_2} - {\rm{O}} - {\rm{C}}{{\rm{H}}_2} - {\rm{C}}{{\rm{H}}_3}$ reacts with hot and excess HI, then formed product is

Ether on reaction with excess of HI produce two molecules of alkyl halide. When equimolar quantities of ether and HI are present, then one molecule of alkyl halide and one molecule of alcohol are formed.

${\rm{C}}{{\rm{H}}_3} - {\rm{C}}{{\rm{H}}_2} - {\rm{I\;and\;C}}{{\rm{H}}_3}{\rm{C}}{{\rm{H}}_2}{\rm{OH}}$

${\rm{C}}{{\rm{H}}_3} - {\rm{C}}{{\rm{H}}_2} - {\rm{OH}}$

The correct Option is "${\rm{C}}{{\rm{H}}_3} - {\rm{C}}{{\rm{H}}_2} - {\rm{I}}$"

Catechol is most acidic out of all dihydric phenols. The reaction is Williamson’s synthesis type reaction.

Predominant product is

The correct Option is "${{\rm{R}}_3}{\rm{N}} - {\rm{C}}{{\rm{H}}_2} - {\rm{C}}{{\rm{H}}_2} - {\rm{Br}}$"

When aromatic carboxylic acids are subjected to Birch reduction $ie,\;{\rm{Na }}\;{\rm{or}}\;{\rm{ K}}\;{\rm{ in}}\;{\rm{ N}}{{\rm{H}}_3}$ and an alcohol), 1, 4-additional of hydrogen takes place and 1, 4-cyclohexadiene carboxylic acids are produced

1, 2 diketone undergoes rearrangement to $\alpha - $ hydroxy carboxylic acid in presence of base. This reaction is known as benzilic acid rearrangement

$\phi {\rm{CHO}} + {\rm{N}}{{\rm{H}}_3} \to $? Product is

Bezaldehyde does not yield a simple addition product with ammonia, but forms a complex product, hydrobenzamide (90%)

The given reaction is an example of Diels-Alder reaction, which is a cycloaddition

When benzyl chloride is boiled with aqueous solution of lead nitrate in current of carbon dioxide, the main product is:

Lab method for preparation of benzaldehyde.

The correct Option is "Benzaldehyde"

In the reaction of carboxylic acid with diazomethane, methyl esters are produced with liberation of ${{\rm{N}}_2}$

Which of the product is formed when acetone is reacted with barium hydroxide solution?

When treated with ${\rm{Ba}}{\left( {{\rm{OH}}} \right)_2},$ acetone undergoes aldol condensation to form diacetone alcohol.

The correct Option is "$\begin{array}{l} \;\;\;\;\;\;\;\;\;{\rm{O }}\;\;\;\;\;\;\;\;\;\;\;{\rm{C}}{{\rm{H}}_3}\\ \;\;\;\;\;\;\;\;\;\;\parallel \;\;\;\;\;\;\;\;\;\;\;\;\;\;\;|\\ {\rm{C}}{{\rm{H}}_3} - {\rm{C}} - {\rm{C}}{{\rm{H}}_2} - {\rm{C}} - {\rm{C}}{{\rm{H}}_3}\\ \;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;|\\ \;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;{\rm{OH}} \end{array}$"

$\begin{array}{l} \;\;\;\;\;\;\;\;\;{\rm{O }}\;\;\;\;\;\;\;\;\;\;\;\\ \;\;\;\;\;\;\;\;\;\;\parallel \;\;\;\;\;\;\;\;\;\;\;\;\;\\ {\rm{C}}{{\rm{H}}_3} - {\rm{C}} - {\rm{CH}} - {\rm{CH}} - {\rm{C}}{{\rm{H}}_3}\\ \;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;|\;\;\;\;\;\;\;\;\;\;|\\ \;\;\;\;\;\;\;\;\;\;\;\;{\rm{C}}{{\rm{H}}_3}\;\;\;\;\;\;{\rm{OH}}\\ \;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\; \end{array}$

$\begin{array}{l} \;\;\;\;\;\;\;\;\;{\rm{O }}\;\;\;\;\;\;\;\;\;\;\;\\ \;\;\;\;\;\;\;\;\;\;\parallel \;\;\;\;\;\;\;\;\;\;\;\;\;\\ {\rm{C}}{{\rm{H}}_3} - {\rm{C}} - {\rm{CH}} - {\rm{CH}} - {\rm{C}}{{\rm{H}}_3}\\ \;\;\;\;\;\;\;\;\;\;|\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;|\\ \;\;\;\;\;\;\;\;{\rm{OH}}\;\;\;\;\;\;\;\;\;\;\;{\rm{C}}{{\rm{H}}_3} \end{array}$

$\begin{array}{l} \;\;\;\;\;\;\;\;{\rm{OH}}\;{\rm{ OH}}\;\\ \;\;\;\;\;\;\;\;\;\;\;|\;\;\;\;\;\;|\\ {\rm{C}}{{\rm{H}}_3} - {\rm{C}} - {\rm{C}} - {\rm{C}}{{\rm{H}}_3}\\ \;\;\;\;\;\;\;\;\;\;|\;\;\;\;\;|\\ \;\;\;\;\;\;{\rm{C}}{{\rm{H}}_3}\;\;{\rm{C}}{{\rm{H}}_3} \end{array}$

The $\alpha ,\beta - $ unsaturated ketones add on ammonia to form $\beta - $ amino compounds

$\alpha ,\beta - $ unsaturated acids add on halogen acids. The mode of addition is contrary to Markownikff’s rule and may be described to the inductive effect of the carboxyl group.

Which one of the following product is formed when calcium salt of adipic acid is heated?

Calcium adipate on dry distillation gives cyclopentanone.

$\begin{array}{l} {\rm{C}}{{\rm{H}}_2}{\rm{C}}{{\rm{H}}_2}{\rm{COOH}}\\ \;\;\;\;\;\;\;\;\;\;|\\ {\rm{C}}{{\rm{H}}_2}{\rm{C}}{{\rm{H}}_2}{\rm{COOH}} \end{array}$

When primary amine reacts with chloroform in ethanoic KOH, then the product is

The correct Option is "Iso cyanide"

Which product is obtained on reduction of methanal in the presence of concentrated NaOH?

$\begin{array}{l} {\rm{HCHO}}\xrightarrow{{{\rm{Conc}}{\rm{.NaOH}}}}{\rm{HCOOH}} + {\rm{C}}{{\rm{H}}_3}{\rm{OH}}\\ methanal\;\;\;\;\;\;\;\;\;\;\;\;formic\;acid\;\;\;methyl\;alcohol \end{array}$ Thus, reaction is called Cannizaro’s reaction.

The correct Option is "Formic acid and methyl alcohol"

${\rm{OHC}}{\left( {{\rm{C}}{{\rm{H}}_2}} \right)_3}{\rm{COC}}{{\rm{H}}_3}\xrightarrow[\Delta ]{{{\rm{O}}{{\rm{H}}^ - }}}$? Major product is

In the presence of base catalyst, intramolecular aldol condensation and ring closure takes place

An amine reacts with ${{\rm{C}}_6}{{\rm{H}}_5}{\rm{S}}{{\rm{O}}_2}{\rm{Cl}}$ and the product is soluble in alkali, amine is:

$R{\rm{N}}{{\rm{H}}_2} + \mathop {{{\rm{C}}_6}{{\rm{H}}_5}{\rm{S}}{{\rm{O}}_2}{\rm{Cl}} \to {{\rm{C}}_6}{{\rm{H}}_5}{\rm{S}}{{\rm{O}}_2}}\limits_{{\rm{(Sulphonamide\;}}\,\,{\rm{soluble }}\,{\rm{in}}\,{\rm{ alkali)}}} {\rm{NH}}R$

The correct Option is "$1^\circ $"

${\rm{HP}}{{\rm{O}}_3} + {{\rm{H}}_2}{\rm{O\;}}\mathop \to \limits^{{\rm{Heat}}} ?$ The product is:

$HP{O_3} + {H_2}O \to {H_3}P{O_4}$

${{\rm{H}}_4}{{\rm{P}}_2}{{\rm{O}}_7}$

${{\rm{H}}_3}{\rm{P}}{{\rm{O}}_3}$

The correct Option is "${{\rm{H}}_3}{\rm{P}}{{\rm{O}}_4}$"

Which one of following is complex V of the ETS of inner mitochondrial membrane?

The complex V of ETS of mitochondrial membrane is ATP synthase, which has a head piece, stalk and a base piece. Out of these, the head piece is identified as the coupling factor 1(F1), stalk portion is necessary for binding i to inner mitochondrial membrane and base piece is isolated as F$_0$ and present within the inner mitochondrial membrane.

The correct Option is "ATP synthase"

When two photosystem (I and II) work in a series, the phosphorylation is called

ATP is synthesised by cells (in mitochondria and chloroplasts) and the process is named as phosphorylation. Photophosphorylation is the synthesis of ATP from ADP and inorganic phosphate in the presence of light. When the two photosystems work in a series, first PS-II and then the PS-I, a process called non-cyclic photophosphorylation occurs. The two photosystem are connected through an electron transport chain, as seen earlier- in the Z scheme. Both ATP and NADPH + H^+ are synthesised by this kind of electron flow. When only PS-I is functional, the electron is circulated within the photosystem and the phosphorylation occurs due to the cyclic flow of electrons

The correct Option is "Non-cyclic"

Bakane’ (foolish seedling) disease of rice seedlings, was caused by

The effect of gibberellins had been know in Japan for over a century where a certain rice plant were found to suffer from ‘Bakane’ (foolish seedlings) disease. The disease was found by Kurosawa (1926) and it is caused by a fungus (Gibberella fujikuroi)

Protein synthesis takes place in

Protein synthesis is also known as translation. Protein synthesis takes place in ribosomes.

The correct Option is "Ribosome"

What helps in flowering?

Phytochrome is an amorphous photoreceptor protein pigment. It exists in two states, i.e., phytochrome Red $({{\mathop{\rm P}\nolimits} _r})$ and phytochrome far-red $\left( {{{\rm{P}}_{{\rm{fr}}}}} \right)$.It is considered that during the day, $\left( {{{\rm{P}}_{{\rm{fr}}}}} \right)$from of the phytochrome is accumulated in the plant which is inhibitory to flowering in short-day plants, but is stimulatory in long day plants.

The correct Option is "Phytochrome"

Many physiological functions are performed by proteins. One such function involves that some proteins discharge

Certain proteins form enzymes, some coenzymes and many hormones (insulin, parathormone) and regulate metabolism. They are called functional proteins

The correct Option is "Hormones"

Pigment making colours of flowers

Pigment conferring colour to skin

Deficiency of which of the given sets of elements causes necrosis?

Necrosis refers to death of leaf tissue. It is caused due to deficiency of Ca, Mg, Cu, K.

The correct Option is "Ca, Mg, Cu and K"

In wind pollination the pollens are feathery, whether it is

True, because due to the presence of feathers they can cover more distance

Sometimes (a) and sometimes (b)

The surface of the endoplasmic reticulum (ER) is covered with

Endoplasmic reticulum is a network of 60 nm diameter. The surface of rough endoplasmic reticulum is covered by ribosomes. Ribosomes are the site of protein synthesis.

The correct Option is "Ribosome"

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