Given, ${C_{\left( {{\rm{graphite}}} \right)}} + {O_2}\left( g \right) \to C{O_2}\left( g \right);$ <Br> $\begin{array}{l}
{\Delta _r}H^\circ = - 393.5\,kJ\,mo{l^{ - 1}}\\
{H_2}\left( g \right) + \frac{1}{2}{O_2}\left( g \right) \to {H_2}O\left( l \right);\\
{\Delta _r}H^\circ = - 285.8\,kJ\,mo{l^{ - 1}}\\
C{O_2}\left( g \right) + 2{H_2}O\left( l \right) \to C{H_4} + 2{O_2}\left( g \right);\\
{\Delta _r}H^\circ = - 890.3\,kJ\,mo{l^{ - 1}}
\end{array}$ <Br> Based on the above thermochemical equations, the value of ${\Delta _r}H^\circ $ at 298 K for the reaction, ${C_{\left( {{\rm{graphite}}} \right)}} + 2{H_2}\left( g \right) \to C{H_4}\left( g \right)$ will be Failed to load question data. Please try again later.
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