A uniform rod of length 200 cm mass 500 g is balanced on a wedge placed at 40 cm mark. A mass of 2kg is suspended from the rod at 20 cm and another unknown mass '$m$' is suspended from the rod at 160 cm mark as shown in the figure. Find the value of '$m$' such that the rod is in equilibrium. $(g = 10\,\,{\rm{m/}}{{\rm{s}}^2})$<br />.