A submarine experience a pressure of $5.05 \times {10^6}\,{\rm{Pa}}$ at a depth of ${d_1}$ in a sea. When it goes further to a depth of ${d_2}$, it experiences a pressure of $8.08 \times {10^6}Pa$, then ${d_2} - {d_1}$ is approximately <Br> (Density of water $ = {10^3}kg/{m^3}$ and acceleration due to gravity $ = 10m{s^{ - 2}}$)Failed to load question data. Please try again later.
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