A spherical surface of radius of curvature $R$ separates air (refractive index ${\rm{1}}{\rm{.0}}$) from glass (refractive index ${\rm{1}}{\rm{.5}}$). The centre of curvature is in the glass. A point object $P$ placed in air is found to have a real image $Q$ in the glass. The line $PQ$cuts the surface at a point $O$, and ${\rm{PO}} = {\rm{OQ}}$. The distance $PO$ is equal toFailed to load question data. Please try again later.
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