A series LCR circuit is connected to an ac voltage source. When ${\rm{L}}$ is removed from the circuit, the phase difference<br />between current and voltage is $\frac{\pi }{3}$. If instead ${\rm{C}}$ is removed from the circuit, the phase difference is again $\frac{\pi }{3}$ between<br />current and voltage. The power factor of the circuit is:Failed to load question data. Please try again later.
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