40% of a mixture of 0.2 mole of ${{\rm{N}}_2}$ and 0.6 mole of ${{\rm{H}}_2}$ react to give ${\rm{N}}{{\rm{H}}_3}$ according to the equation,${{\rm{N}}_2}\left( {\rm{g}} \right) + 3{{\rm{H}}_2}\left( {\rm{g}} \right)\leftrightharpoons2{\rm{N}}{{\rm{H}}_3}\left( {\rm{g}} \right)$ at constant temperature and pressure. Then the ratio of the final volume to the initial volume of gases is :Failed to load question data. Please try again later.
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