0.27 g of a long chain fatty acid was dissolved in $100{\rm{ \,\,c}}{{\rm{m}}^3}$ of hexane. 10 mL of this solution was added dropwise to the surface of water in a round watch glass. Hexane evaporates and a monolayer is formed. The distance from edge to centre of the watch glass is 10 cm. What is the height of the monolayer? [Density of fatty acid ${\rm{ = 0}}{\rm{.9 \,g \,c}}{{\rm{m}}^{ - {\rm{3}}}};\pi = 3]$Failed to load question data. Please try again later.
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