${\rm{KMn}}{{\rm{O}}_4}$ (mol.wt.= 158) oxidizes oxalic acid in acid medium to ${\rm{C}}{{\rm{O}}_2}$ and water as follows<br />$5{{\rm{C}}_2}{\rm{O}}_4^{2 - } + 2{\rm{MnO}}_4^ - + 16{{\rm{H}}^ + } \to 10{\rm{C}}{{\rm{O}}_2} + 2{\rm{M}}{{\rm{n}}^{2 + }} + 8{{\rm{H}}_2}{\rm{O}}$<br />What is the equivalent weight of ${\rm{KMn}}{{\rm{O}}_4}$?Failed to load question data. Please try again later.
NEET Information
- NEET 2024
- NEET Syllabus
- NEET Application Process
- NEET Seat Intake