The Question is from Physics System of particles Rotational inertia of solid bodies, and it was created by the author Mr. ANIL KUMAR.G

Question

A system consists of two identical spheres each of mass 1.5 kg and radius 50 cm at the end of light rod. The distance between the centres of the two spheres is 5 m. what will be the moment of inertia of the system about an axis perpendicular to the rod passing through its mid-point?

Mr. ANIL KUMAR.G · Accepted Answer

Given, mass of each sphere, M=1.5 kg
Radius of each sphere, R=50 cm $ = 50 imes {10^{ - 2}}\,\,{ m{m}}$
Distance between centre of spheres, $l = 5\,\,{ m{m}}$
By using parallel axis theorem, moment of inertia of system is
$I = 2\left[ {\frac{2}{5}M{R^2} + \frac{{M{l^2}}}{4}} ight]$
$I = 2M\left[ {\frac{2}{5}{R^2} + \frac{{{l^2}}}{4}} ight]$
Substituting the values, we get
$I = 2 imes 1.5\left[ {\frac{2}{5} imes {{\left( {50 imes {{10}^{ - 2}}} ight)}^2} + \frac{{{{(5)}^2}}}{4}} ight]$
$ = 19.05\,\,\,kg\,{m^2}$

Mr. ANIL KUMAR.G · Answer

$18.75\,\,\,kg\,{m^2}$

Mr. ANIL KUMAR.G · Answer

$1.905 	imes {10^5}\,\,kg{m^2}$

Mr. ANIL KUMAR.G · Answer

The correct Option is "$19.05\,\,\,kg{m^2}$"

Mr. ANIL KUMAR.G · Answer

$1.875 	imes {10^5}\,\,kg{m^2}$

NEET Information

NEET TEST PREP

Company