Two point charges $100\mu C{\rm{\;and\;}}5\mu C$ are placed at points $A{\rm{\;and\;}}B$ respectively with $AB = 40\;cm.$ The work done by external force in displacing the charge $5{\rm{\;}}\;\mu C$ from $B{\rm{\;to\;}}C,$ where $BC = 30\;cm$ angle $ABC = \frac{\pi }{2}$ and $\frac{1}{{4\pi {\varepsilon _0}}} = 9 \times {10^9}N{m^2}/{C^2}$Failed to load question data. Please try again later.
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