Two particles undergo SHM along the same line with the same time period (T) and equal amplitude (A). At a particular instant one is at $x=-A$ and the other is at $x=0$. If they start moving in the same direction then they will cross each other at <br> (i) $t=\frac{4 T}{3}$ <br> (ii) $t=\frac{3 T}{8}$ <br> (iii) $x=\frac{A}{2}$ <br> (iv) $x=\frac{A}{\sqrt{2}}$ <br> Failed to load question data. Please try again later.
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