The standard reduction potential ${E^ \circ }$ for half reactions are <br>
Zn = ${\rm{Z}}{{\rm{n}}^{2 + }}$ + Ze ${E^ \circ }$ = + 0.76 V <br>
Fe = ${\rm{F}}{{\rm{e}}^{2 + }}$ + Ze ${E^ \circ }$ = + 0.41 V <br>
The emf of the cell reaction <br> ${\rm{F}}{{\rm{e}}^{2 + }} + {\rm{Zn}} = {\rm{Z}}{{\rm{n}}^{2 + }} + {\rm{Fe}}$ is:
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