As shown in the figure, a metallic rod of linear density $0.45 \mathrm{~kg} \mathrm{~m}^{-1}$ is lying horizontally on a smooth inclined plane which makes an angle of $45^{\circ}$ with the horizontal. The minimum current flowing in the rod required to keep it stationary, when $0.15 \mathrm{~T}$ magnetic field is acting on it in the vertical upward direction, will be : $\left\{\right.$ Use $\left.g=10 \mathrm{~m} / \mathrm{s}^2\right\}$ <Br>